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ZMT zurich med tech

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  4. Homogeneity of E-filed map in plane wave simulation

Homogeneity of E-filed map in plane wave simulation

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  • SylvainS Offline
    SylvainS Offline
    Sylvain
    ZMT
    wrote on last edited by
    #2

    Hello, please add a screenshot or two, comparing the E-field in each of the 3 planes (including the colorbar, so that we can see the magnitude of the field). This way, it will be clear what you mean by "not homogeneous".

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    • SylvainS Sylvain

      Hello, please add a screenshot or two, comparing the E-field in each of the 3 planes (including the colorbar, so that we can see the magnitude of the field). This way, it will be clear what you mean by "not homogeneous".

      S Offline
      S Offline
      Saya
      wrote on last edited by
      #3

      @Sylvain plane wave.png

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      • S Offline
        S Offline
        Saya
        wrote on last edited by Saya
        #4

        The pink box is plane wave source and as it could be seen the E-field is homogeneous in yz-plane but not in two others.

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        • S Saya

          The pink box is plane wave source and as it could be seen the E-field is homogeneous in yz-plane but not in two others.

          S Offline
          S Offline
          Saya
          wrote on last edited by
          #5

          @Saya 8958309f-36b6-497f-aa85-3df62c87b25b-image.png

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          • SylvainS Offline
            SylvainS Offline
            Sylvain
            ZMT
            wrote on last edited by
            #6

            One interpretation of your results could be that the wave is dissipating energy while traveling (in the x direction). Reasons for dissipation could be physical (if there is a lossy material inside the pink box), or numerial (if the grid is too coarse, or if the simulation did not run for a long enough time and did not converge).
            I would suggest to run the same simulation with a finer grid and check if there is any difference in the results.

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            • S Offline
              S Offline
              Saya
              wrote on last edited by
              #7

              The material is just dielectric gel. I'll check your suggestions. Thanks.

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              • SylvainS Offline
                SylvainS Offline
                Sylvain
                ZMT
                wrote on last edited by
                #8

                If there is a gel, I would expect it is dissipating some power (just check the SAR, for instance...). In that case, you should expect the E field to decrease in intensity in the direction of propagation.

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                • S Offline
                  S Offline
                  Saya
                  wrote on last edited by
                  #9

                  I'm wondering why energy dissipation does not happen in z-direction (since in yz plane E-field is homogeneous)?

                  S SylvainS 2 Replies Last reply
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                  • S Saya

                    I'm wondering why energy dissipation does not happen in z-direction (since in yz plane E-field is homogeneous)?

                    S Offline
                    S Offline
                    Saya
                    wrote on last edited by
                    #10

                    @Saya ed1dd158-ffcc-47ae-98f1-91a0a3864050-image.png

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                    • S Offline
                      S Offline
                      Saya
                      wrote on last edited by
                      #11

                      I ran the simulation with a finer grid and for a longer time, but the result is still the same.

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                      • S Saya

                        I'm wondering why energy dissipation does not happen in z-direction (since in yz plane E-field is homogeneous)?

                        SylvainS Offline
                        SylvainS Offline
                        Sylvain
                        ZMT
                        wrote on last edited by
                        #12

                        @Saya said in Homogeneity of E-filed map in plane wave simulation:

                        I'm wondering why energy dissipation does not happen in z-direction (since in yz plane E-field is homogeneous)?

                        Because your wave is propagating in the X direction.

                        Your simulation results make perfect sense: a wave is propagating through a lossy medium, dissipating some energy in the process.

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                        • S Offline
                          S Offline
                          Saya
                          wrote on last edited by Saya
                          #13

                          So you mean in the simulation with gel, because of the power loss in x direction, E-field should be non homogeneous in xz and xy planes.
                          I checked the simulation without gel(with just air) and it seems E-field is homogeneous in all planes. Great. Thanks.
                          And two more questions,

                          • Why in the tutorial, the air is considered as gel and gel is not used as an object in the simulation?
                          • Where is the starting point of the wave propagation?
                            Thanks.
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                          • SylvainS Offline
                            SylvainS Offline
                            Sylvain
                            ZMT
                            wrote on last edited by
                            #14
                            • The "air" is not considered as "gel". Rather, the background material, which is by default "air", is set to "gel" instead. The background is not an object itself: it is the space that is not occupied by any object. As such, it does not have an explicit shape, but it has material properties.
                            • For a plane wave source, the E and H fields are imposed (based on the analytical expression of a plane wave) on the face(s) "upwind" from the direction of propagation. Note that this is an idealized concept, as true plane waves don't exist in nature (https://en.wikipedia.org/wiki/Plane_wave)
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                            • S Offline
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                              Saya
                              wrote on last edited by
                              #15

                              Thanks for your explanation. But I'm still wondering why the background is set to gel? Why the gel is not used as an object?

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                              • SylvainS Offline
                                SylvainS Offline
                                Sylvain
                                ZMT
                                wrote on last edited by
                                #16

                                I'm not sure. Maybe because you would then have to consider the size and shape of said object, its interface with the "background", possible intersection with the sides of the computational domain (which the plane wave source may not allow), etc... All of that for zero benefit, since the medium of propagation is a gel, not air or vaccuum.

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                                • S Offline
                                  S Offline
                                  Saya
                                  wrote on last edited by
                                  #17

                                  Right. Thank you very much for your explanation and comments.

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